1)
дано
m(Ca)=20 g
HF
------------------
m(H2)-?
V(H2)-?
20 Xg
Ca+2HF-->CaF2+H2 M(Ca)=40 g/mol ,M(H2)=2g/mol
40 2
X(H2)=20*2/40=1 g
n=m/M=1/2=0.5 mol
V(H2)=n*Vm=0.5*22.4=11.2 L
ответ 1 г, 11.2 л
2)
дано
m(KCLO3)=55 g
---------------------
m(O2)-?
V(O2)-?
55 xg
2KCLO3-->2KCL+3O2 M(KCLO3)=122.5 g/mol , M(O2)=32 g/mol
2*122.5 3*32
X(O2)=55*96/245
X=21.55 g
n(O2)=m/M=21.55/32=0.67 mol
V(O2)=n*Vm=0.67*22.4=15 л
ответ 21.55 г , 15 л
1)
дано
m(Al)=13 g
HCL
------------------
m(H2)-?
V(H2)-?
13 Xg
2Al+6HCL-->2AlCL3+3H2 M(AL)=27 g/mol M(H2)=2 g/mol
2*27 3*2
X=13*6/54
X=1.44 g
n(H2)=m/M=1.44/2=0.72 mol
V(H2)=n*Vm=0.72*22.4=16.13 л
ответ 1.44 г, 16.13 л
2)
дано
V(NH3)=17 л
---------------
m(NO)-?
V(NO)-?
m(O2)-?
V(O2)-?
m(H2O)-?
V(H2O)-?
17L XL X1L X2L
4NH3+5O2-->4NO+6H2O
4mol 5mol 4mol 6mol
4*17 5*32 4*30 6*18
M(NH3)=17 g/mol
M(O2)=32 g/mol
M(NO)=30 g/mol
M(H2O)=18 g/mol
X(O2)=17*5/4=21.25 л
X1(NO)=17*4/4 = 17 л
X2(H2O)=17*6/4=25.5 л
X(O2)=17*160/68 = 40 g
X1(NO)=17*120 / 68 = 30 g
X2(H2O) = 17*108 / 68 = 27 g