Решите систему пожалуйста

Решите задачу:

$\left \{ {{\log_{3}x+\log_{3}y=3,} \atop {y-x=2;}} \right. \\ x\ \textgreater \ 0, \ y\ \textgreater \ 0, \\ \left \{ {{\log_{3}xy=3,} \atop {y=x+2;}} \right. \ \left \{ {{\log_{3}x(x+2)=\log_{3}3^3,} \atop {y=x+2;}} \right. \ \left \{ {{x^2+2x=27,} \atop {y=x+2;}} \right. \\ x^2+2x-27=0, \\ D_1=1+27=28, \\ x_1=-1-2\sqrt{7}\ \textless \ 0, \ x_2=-1+2\sqrt{7}, \\ \left \{ {{x=2\sqrt{7}-1,} \atop {y=2\sqrt{7}+1.}} \right.$