Решить систему уравнений

$\left\{\begin{array}{l} 5^{x+1}\cdot3^y=75 \\ 3^x\cdot5^{y-1}=3 \end{array}$
$\left\{\begin{array}{l} 5\cdot 5^x\cdot3^y=75 \\ 3^x\cdot \frac{1}{5} \cdot 5^y=3 \end{array}$
$\left\{\begin{array}{l} 5^x\cdot3^y=15 \\ 3^x\cdot 5^y=15 \end{array}$
$\dfrac{5^x\cdot3^y}{3^x\cdot5^y} = \dfrac{15}{15}$
$\left( \dfrac{5}{3} \right)^x\cdot \left( \dfrac{3}{5} \right)^y=1 \\\\ \left( \dfrac{5}{3} \right)^x\cdot \left( \dfrac{5}{3} \right)^{-y}=1 \\\\ \left( \dfrac{5}{3} \right)^{x-y}=\left( \dfrac{5}{3} \right)^0 \\\\ x-y=0 \\\ \Rightarrow x=y \\\ 5^x\cdot3^x=15 \\\ (5\cdot3)^x=15 \\\ 15^x=15^1 \\\ \Rightarrow x=1 \\\ \Rig$
Ответ: (1; 1)