1)x+√x=2(x-1) 2) √5x+√(14-x)=8

Question

1)x+√x=2(x-1)
2) √5x+√(14-x)=8

Answer 1

1) x+√x=2(x-1);⇒x≥0;
√x=-x+2x-2;⇒√x=x-2;⇒x-2≥0;x≥2;
(√x)²=(x-2)²;
x=x²-4x+4;
x²-5x+4=0;
x₁,₂=5/2⁺₋√((25/4)-4)=5/2⁺₋3/2;
x₁=(5+3)/2=4;
x₂=(5-3)/2=1⇒решения нет;
2) √(14-x)=8-√5x