Решите уравнение 2 sin⁡ (x-π/3)-√3≤0

Question

Решите уравнение 2 sin⁡ (x-π/3)-√3≤0

Answer 1

2sin(x-π/3)<√3<br>sin(x-π/3)<√3/2<br>2π/3+2πn≤x-π/3≤7π/3+2πn
2π/3+π/3+2πn≤x≤7π/3+π/3+2πn
x∈[π=2πn;8π/3+2πn,n∈z]