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Решите задачу:

$1)\frac{1}{6}x-0,82=\frac{3}{8}x-1,37\\\frac{1}{6}x-\frac{3}{8}x=0,82-1,37\\\frac{4x-9x}{24}=-0,55\\-5x=-13,2\\x=2,64\\2) 7,6:x=\frac{19}{9}:\frac{22}{9}\\7\frac{3}{5}x=\frac{19}{9}\cdot \frac{9}{22}\\\frac{38}{5}x=\frac{19}{22}\\x=\frac{19}{22}\cdot \frac{5}{38}\\x=\frac{5}{44}\\3) 20-18,6:(6\frac{11}{15}-4\frac{3}{20})=20-18\frac{3}{5}:(\frac{101}{15}-\frac{83}{20})=\\=20-\frac{93}{5}:\frac{404-249}{60}=20-\frac{93}{5}\cdot \frac{60}{155}=$
$=20-\frac{3\cdot 12}{5}=\frac{100-36}{5}=\frac{64}{5}=12,8$