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Решите задачу:

$...=\frac{3(\frac{1}{2}\cdot \frac{4}{5}+\frac{7}{5}\cdot \frac{7}{11}-\frac{3}{11})}{(\frac{3}{2}+\frac{1}{4})\cdot \frac{3}{55}}=\\=\frac{3(\frac{2}{5}+\frac{49}{55}-\frac{3}{11})}{\frac{7}{4}\cdot {\frac{3}{55}}}=\frac{3(\frac{2}{5}+\frac{46}{11})}{\frac{21}{220}}=\\=\frac{3\cdot \frac{252}{55}}{\frac{21}{220}}=\frac{3\cdot 252\cdot 220}{55\cdot 21}=3\cdon 12\cdot 4=144$