№1. 2а²b = m
a) 4a⁴b² = 2a²b × 2a²b = (2a²b)² , где 2а²b = m => 4a⁴b² = m²
б) 40a^6 × b³ = 2a²b × 20a⁴b² , где 2а²b = m => 40a^6 × b³ = 20a⁴b²m
№2. (-3/7) × x²y³z² + m = x²y³z²
m = x²y³z² - (-3/7) × x²y³z²
m = x²y³z² + (3/7) × x²y³z²
m = (10/7) × x²y³z²
m = (1 целая 3/7) × х²y³z²
Ответ: (1 целая 3/7) × x²y³z²
№3. a) 5,3a^5 × b²c = 3a^5 × b²c + 2,3a^5 × b²c
б) 5,3а^5 × b²c = 7,5a^5 × b²c - 2,2a^5 × b²c