Sin5x-√3cos5x=2 ....

Question

Sin5x-√3cos5x=2 ....

Answer 1

Sin5x-√3cos5x=2
2(sin5x*1/2-cos5x*√3/2)=2
sin5xcosπ/3-cos5xsinπ/3=1
sin(5x-π/3)=1
5x-π/3=π/2+2πn,n∈z
5x=5π/6+2πn,n∈z
x=π/6+2πn/5,n∈z