Номер 635 решите пожалуйста

Решите задачу:

$1)\;\frac{\left|\frac49-\frac56\right|\cdot\left|\frac{11}{14}+\frac12\right|}{(-1,2)\cdot\left|\frac16-\frac18\right|}=\frac{\left|\frac8{18}-\frac{15}{18}\right|\cdot\left|\frac{11}{14}+\frac7{14}\right|}{(-1,2)\cdot\left|\frac4{24}-\frac3{24}\right|}=\frac{\left|-\frac7{18}\right|\cdot\left|\frac{18}{14}\right|}{(-1,2)\cdot\left|\frac1{24}\right|}=\frac{\frac7{18}\cdot\frac{18}{14}}{\left(-\frac{12}{10}\right)\cdot\frac1{24}}=\\=\frac{\frac12}{\left(-\frac1{20}\right)}=-\frac12\cdot\frac{10}1=-5$

$2)\;\frac{\left|\frac5{12}-\frac4{15}\right|\cdot\left|\frac1{18}+\frac12\right|}{\left|\frac23-\frac58\right|\cdot(-8)}=\frac{\left|\frac{25}{60}-\frac{16}{60}\right|\cdot\left|\frac1{18}+\frac9{18}\right|}{\left|\frac{16}{24}-\frac{15}{24}\right|\cdot(-8)}=\frac{\left|\frac9{60}\right|\cdot\left|\frac{10}{18}\right|}{\left|\frac1{24}\right|\cdot(-8)}=\frac{\frac9{60}\cdot\frac{10}{18}}{\frac1{24}\cdot(-8)}=\\=\frac{\frac1{12}}{\left(-\frac13\right)}=-\frac1{12}\cdot3=-\frac14$