Напишіть будь ласка 9,10,11

$5^{2x+5} - 2^{2x+10} + 3*5^{2x+2} - 2^{2x+3} = 0|:2^{2x+2}\\ 125*( \frac{5}{2} )^{2x+2}-2^8+3* (\frac{5}{2} )^{2x+2} - 2 = 0\\ ( \frac{5}{2} )^{2x+2} = t\\ 125t - 256 +3t-2=0\\ 128t=258\\ t= \frac{129}{64}\\ ( \frac{5}{2} )^{2x+2} = \frac{129}{64} \\ ( \frac{5}{2} )^{2x} = \frac{129}{400} \\ ( \frac{5}{2} )^{x} = \frac{ \sqrt{129}}{20} \\ x = log_{2,5}\frac{ \sqrt{129}}{20}$

10
$2^{2x-1}+2^{2x-2}+2^{2x+2}=2^{2x-3} + 78\\ 2^{2x-3}(2^2+2+2^5-1)=78\\ 2^{2x-3}(4+2+32-1)=78\\ 2^{2x-3}*37=78\\ 2^{2x} = \frac{78*8}{37} = \frac{624}{37} \\ 2^x = \sqrt{ \frac{624}{37}} \\ x = log_2\sqrt{ \frac{624}{37}}$

11.
$5^{1+x^2}-5^{1-x^2}=24|*5^{x^2}\\ 5*5^{2x^2}-5=24*5^{x^2}\\ 5^{x^2} = t,t\ \textgreater \ 0\\ 5t^2-24t - 5=0\\ D = 576+100 = 676\\ t = \frac{24+26}{10} =5\\ 5^{x^2} = 5^1\\ x^2=1\\ x_1=-1\\ x_2=1$