49\12 * 99\154 + 28\21 * 99\154

Решите задачу:

$\frac{49}{12} * \frac{99}{154} + \frac{28}{21} * \frac{99}{154} = ( \frac{49}{12} + \frac{28}{21} ) \frac{99}{154} \\ 1) \frac{49}{12} + \frac{28}{21} = \frac{49}{12} + \frac{4}{3} =\frac{49}{12} + \frac{16}{12} = \frac{65}{12} \\ 2) \frac{65}{12} *\frac{99}{154} =\frac{65}{12} *\frac{9}{14} = \frac{65*3}{4*14} =\frac{195}{56} =3\frac{27}{56}$