Помогите пожалуйста log 1/2(3-2x)>-1

$log_{ \frac{1}{2} }(3-2x)\ \textgreater \ -1$
ОДЗ:
$3-2x\ \textgreater \ 0$
$-2x\ \textgreater \ -3$
$x\ \textless \ 1.5$
$log_{ \frac{1}{2} }(3-2x)\ \textgreater \ log_{ \frac{1}{2} }( \frac{1}{2})^{-1}$
$3-2x\ \textless \ ( \frac{1}{2})^{-1}$
$3-2x\ \textless \ 2$
$-2x\ \textless \ 2-3$
$-2x\ \textless \ -1$
$x\ \textgreater \ 0.5$
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------(0.5)--------------(1.5)----------------
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Ответ: (0.5; 1.5)