(a²ⁿ⁻¹)ⁿ⁻² *(bⁿ⁻¹)ⁿ⁺¹ *1³ a²ⁿ⁽²⁾⁻⁵ⁿ⁺² *bⁿ⁽²⁾⁻¹
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(bⁿ⁺²)ⁿ⁻² *(a²ⁿ⁻⁷)ⁿ⁺¹ *(a³b)³ bⁿ⁽²⁾⁻⁴ * a²ⁿ⁽²⁾⁻⁵ⁿ⁻⁷*a⁹b³
= a²ⁿ⁽²⁾⁻⁵ⁿ⁺²⁻⁽²ⁿ⁽²⁾⁻⁵ⁿ⁻⁷⁾ ⁻⁹ *bⁿ⁽²⁾⁻¹⁻⁽ⁿ⁽²⁾⁻⁴⁾⁻³ =a²ⁿ⁽²⁾⁻⁵ⁿ⁺²⁻²ⁿ⁽²⁾⁺⁵ⁿ⁻⁷ ⁻⁹ *bⁿ⁽²⁾⁻¹⁻ⁿ⁽²⁾⁺⁴⁻³=a⁻¹⁴b⁰=
=a⁻¹⁴=1/a¹⁴