Дано
V(CO2) =11.2 L
KOH
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m(KHCO3)-?
11.2 Xg
KOH+CO2-->KHCO3 M(KHCO3)=100 g/mol, Vm=22.4L/mol
22.4 100
X=11.2*100/22.4=50 g
ответ 50 г
2)
Дано
V(H2CO3)=4.48 L
m(Ca(OH)2)=7.4 g
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n(CaCO3)-?
m(CaCO3)-?
4.48 L 7.4g
H2CO3+Ca(OH)2-->CaCO3+H2O+CO2
M(Ca(OH)2)=74 g/mol , M(CaCO3)=100 g/mol
Vm=22.4L/mol
n(H2CO3)=V/Vm=4.48/22.4=0.2 mol
n(Ca(OH)2)=m/M=7.4/74=0.1 mol
n(H2CO3)>n(Ca(OH)2)
n(Ca(OH)2)=n(CaCO3)=0.1 mol
m(CaCO3)=n*M=0.1*100=10 g
ответ 0.1 моль, 10 г