Решите два примера пожалуйста :з

$1)$

$\left \{ {{3x-4\ \textgreater \ 9x-6} \atop {x-5 \leq 2x+4}} \right.$

$\left \{ {{3x-9x\ \textgreater \ -6+4} \atop {x-2x \leq 4+5}} \right.$

$\left \{ {{-6x\ \textgreater \ -2} \atop {-x \leq9}} \right.$

$\left \{ {{x\ \textless \ \frac{1}{3} } \atop {x \geq -9}} \right.$

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$x$ ∈ $[-9; \frac{1}{3} )$

$2)$

$log_{ \frac{1}{2}}(3x+4) \leq -4$

ОДЗ:
$3x+4\ \textgreater \ 0$
$3x\ \textgreater \ -4$
$x\ \textgreater \ -1 \frac{1}{3}$

$log_{ \frac{1}{2}}(3x+4) \leq log_{ \frac{1}{2}}( \frac{1}{2}) ^{-4}$

$log_{ \frac{1}{2}}(3x+4) \leq log_{ \frac{1}{2}}16$

$3x+4 \geq 16$

$3x \geq 16-4$

$3x \geq 12$

$x \geq4$

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Ответ: $[4;+$ ∞ $)$