Решите неравенство а)(3/4)^1-2x>(4/3)^x+5 б)(2/3)^3x-7>(3/2)^4x+1
1 (4/3)^2x-1>(4/3)^x+5 2x-1>x+5 2x-x>5+1 x>6 x∈(6;∞) 2 (3/2)^7-3x>(3/2)^4x+1 7-3x>4x+1 4x+3x<7-1<br>7x<6<br>x<6/7<br>x∈(-∞;6/7)