√ ( 2x - 1 ) + ( 2x - 1 ) = 2
√ 2x - 1 = a
a ≥ 0
a + a² = 2
a² + a - 2 = 0
D = 1 + 8 = 9 ; √ D = 3
a1 = ( - 1 + 3 ) : 2 = 1
a2 = ( - 1 - 3 ) : 2 = - 2 ( ≤ 0 )
√ ( 2x - 1 ) = 1
( √ ( 2x - 1 ))² = 1²
2x - 1 ≥ 0
2x ≥ 1
x ≥ 0,5
2x - 1 = 1
2x = 2
x = 1
Ответ 1