log4 (3x-1) - log4 (4-x) = 2 - log4 (x-1)
log4(3x-1)-log4(4-x)-2+log4(x-1)=0
log4(3x-1)+log4(x-4)-2+log4(x-1)=0
(3log4x-log4)+(log4x-4log4)-2+(log4x-log4)=0
5log4x-(-log(1¬409600))=0
5log4x=-log(1¬409600)
x=(-log(1¬409600))÷5÷log4
x=-log(1¬409600)¬5log4
ответ:x=-log(1¬409600)¬5log4