1) ( 3sin x/2 - 1) * (√2cos 6x + 1 ) = 0 2) cos x/3 = 0

Question

1)
( 3sin x/2 - 1) * (√2cos 6x + 1 ) = 0
2)
cos x/3 = 0

Answer 1

Ответ. 3*(sin(x))^2-cos(x)+1=0; 3*cos(x))^2+cos(x)-4=0; (3*cos(x)+4)*(cos(x)-1)=0; cos(x1)=1;     нежашто