(5х-3)(х+2)-(х+4)^2=0

Question

(5х-3)(х+2)-(х+4)^2=0

Answer 1

(5х-3)(х+2)-(х+4)^2=0
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(5x-3)(x+2)-(x+4)² = 0 ;
5x² +10x -3x -6 -(x²+8x+16) =0 ;
5x² +7x -6 -x²-8x-16 =0 ;
4x² - x - 22 =0 ;
D =1² -4*4*(-22) =1+16*11*2 =1+176*2 =1+352 =353 .
x₁ =(1 +√353) /2*4 =(1 +√353) / 8  ;
x₂ =(1 -√353) /8 . 

Answer 2

(5х-3)(х+2)-(х+4)²=0
5х²+10х-3х-6-(х²+8х+16)=0
5х²+10х-3х-6-х²-8х-16=0
4х²-х-22=0
D=b²-4ac= 353
x₁,₂=  
x₁= 
x₂=