Х+5/14=5/6 4 5/19+х+1 1/38=12 1/2 17 3/8-y=9 5/12+2 1/6 14 9/16-х=6 3/4+1 2/5 ПОМОГИТЕ...

Решите задачу:

$x+\frac5{14}=\frac56\\x=\frac56-\frac5{14}\\x=\frac{35}{42}-\frac{15}{42}=\frac{10}{42}=\frac5{21}\\\\4\frac5{19}+x+1\frac1{38}=12\frac12\\x=12\frac12-\left(4\frac5{19}+1\frac1{38}\right)\\x=12\frac{19}{38}-\left(4\frac{10}{38}+1\frac1{38}\right)\\x=12\frac{19}{38}-5\frac{11}{38}\\x=7\frac8{38}=7\frac4{19}\\\\17\frac38-y=9\frac5{12}+2\frac16\\y=17\frac38-\left(9\frac5{12}+2\frac16\right)\\y=17\frac9{24}-\left(9\frac{10}{24}+2\frac4{24}\right)\\y=17\frac9{24}-11\frac{14}{24}\\y=5\frac{19}{24}$

$14\frac9{16}-x=6\frac34+1\frac25\\x=14\frac9{16}-\left(6\frac34+1\frac25\right)\\x=14\frac{45}{80}-\left(6\frac{60}{80}+1\frac{32}{80}\right)\\x=14\frac{45}{80}-7\frac{92}{80}\\x=14\frac{45}{80}-8\frac{12}{80}\\x=6\frac{33}{80}$