5(1-y)^2-(3+y)^2-3(1-y)(1+y)
5(1+y²-2y)-3(9+y²+6y)-3(1-y²)=5+5y²-10y-27-3y²-18y-3+3y²= =5y²-28y-25=0 D=1284 =4*321 √D=2√321 x1=1/10[28+2√321] x2=1/10[28-√321]