Решите неравенство 2x^2-6<(3-x)(x+3)

$2x^2-6\ \textless \ (3-x)(x+3) \\ 2 x^{2} -6\ \textless \ (3-x)(3+x)\\2x^2-6\ \textless \ 9- x^{2} \\2 x^{2}+ x^{2} \ \textless \ 9+6\\3 x^{2} \ \textless \ 15\\ x^{2} \ \textless \ 5\\x=+- \sqrt{5} \\ \\ (x- \sqrt{5} )(x+ \sqrt{5} )\ \textless \ 0$

+ - +
-------------|-----------------------------|-------------------------->x
-√5 √5

x∈(-√5;√5)