Помогите 1)2/3*(4-х)=2х+1 1/3 2)5/6*(3-2х)=х-1 1/2

Решите задачу:

$1)\;\frac23\cdot(4-x)=2x+1\frac13\\\frac83-\frac23x=2x+\frac43\\2x+\frac23x=\frac83-\frac43\\\frac83x=\frac43\\x=\frac43:\frac83=\frac43\cdot\frac38=\frac12\\\\2)\;\frac56\cdot(3-2x)=x-1\frac12\\\frac52-\frac53x=x-\frac32\\x+\frac53x=\frac52+\frac32\\\frac83x=\frac82=4\\x=4:\frac83=4\cdot\frac38=\frac32=1\frac12$