2sinx=√3cos(x+π/3)=-1

Question

2sinx=√3

cos(x+π/3)=-1

Answer 1

2sinx=√3
sinx=√3/2
x=(-1)^n  π/3+πn n∈Z

cos(x+π/3)=-1
x+π/3 = π + 2πn n ∈ Z
x=2π/3 + 2πn  n∈Z

Answer 2

Ответ:
1)2sinx=_/3
sinx=_/3/2
x=(-1)^k*arcsin(_/3/2)+pik
x=(-1)^k*pi/3+pik
2)cos(x+pi/3)=-1
x+pi/3=+-accos(-1)+2pik
x+pi/3=+-(pi-arccos1)+2pik   
x=+-((pi-2pi)-pi/3)+2pik
x=+-(-pi-pi/3)+2pik
x=+-(-4pi/3)+2pik