(х+1)^2 (х^2+2х)=0
x+1=0
x=-1
x²+2x=0
x(x+2)=0
x=-2 x=0
(Х^2+3х+1)(х^2+3х+3)=-1
(x²+3x+1)(x²+3x+3)+1=0
(t+1)(t+3)+1=0
(t²+3t+t+3)+1=0
(t²+4t+3)+1=0
t²+4t+3+1=0
t²+4t+4=0
D=b²-4ac=4²-4*1*4=0
t₁.₂=-b/2a=-4/2*1=-2
x²+3x=-2
x²+3x+2=0
X₁.₂-b+-√D
/2a
x₁=-3-1/2*1=-2 x₂=-3+1/2*1=-1
x=-2 x=-1
(Х^2-4х+1)(х^2-4х+2)=12
(t+1)(t+2)-12=0
(t²+2t+t+2)-12=0
(t²+3t+2)-12=0
t²+3t+2-12=0
D=b²-4ac=3²-4*1(-10)=49
t₁.₂=-b+-√D/2a
t₁=-3-7/2*1=-5 t₂=-3+7/2*1=2
x²-4x=-5 x²-4x=2
x²-4x=-5
x²-4x+5=0
x²-4x=2
x²-4x-2=0
D=b²-4ac=(-4)²=4*1(-2)=24
x₁.₂=-b+-√D/2a
x₁=4-2√6/2*1=2-√6 x₂=4+2√6/2*1=2+√6
x=2-√6 x=2+√6
ответ:x=2-√6 x=2+√6
(х^2+1)(х^2+2х)=12
(x²+1)(x²+2x)-12=0
(x^4+2x³+x²+2x)-12=0
x^4+2x³+x²+2x-12=0