(x+3)^4-13(x+3)^2+36=0

Question

(x+3)^4-13(x+3)^2+36=0

Answer 1

(x+3)^4-13(x+3)^2+36=0
t²-13t+36=0
D=b²-4ac=(-13)²-4*1*36=25
t₁.₂=-b+-√D/2a
t₁=13-5/2*1=4 t₂=13+5/2*1=9
(x+3)²=4
(x+3)²-4=0
x+3=2
x=-1
x+3=-2
x=-2-3
x=-5
x=-5 x=-1
(x+3)²=9
(x+3)²=9
(x+3)²=9=0
x+3=3
x=3-3
x=-6
x=-6 x=0
ответ:x=-6 x=-5 x=-1 x=0