Log0.2 x - log5 (x-2) < log0.2 3
одз x>0
x-2>0 x>2
1/5=0.2
log0.2 x + log0.2 (x-2) < log0.2 3
log0.2 x(x-2) < log0.2 3
(0.2-1)(x(x-2)-3)<0<br>x²-2x-3>0
D=4+12=16
x12=(2+-4)/2=3 -1
(x+1)(x-3)>0
+++++++++ (-1) ---------- (3) +++++++++
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ответ x>3 x=(3 +00)