Решение
2 sin(3x-Π/4)+1=0
sin(3x-Π/4) = - 1/2
3x - π/4 = (-1)^n arcsin(- 1/2) + πk, k ∈ Z
3x - π/4 = (-1)^(n+1) arcsin(1/2) + πk, k ∈ Z
3x - π/4 = (-1)^(n+1) *(π/6) + πk, k ∈ Z
3x = (-1)^(n+1) *(π/6) + π/4 + πk, k ∈ Z
x = (-1)^(n+1) *(π/18) + π/12 + πk/3, k ∈ Z