(x+3)^4-13(x+3)^2+36=0
t²-13t+36=0
D=b² -4ac=(-13)² -4*1*36=25
t₁.₂=-b+-√D/2a
t₁13-5/2*1=4 t₂=13+5/2*1=9
(x+3)²=4 (x+3)²=9
(x+3)²-4=0
x+3=2
x=2-3
x=-1
x+3=-2
x=-2-3
x=-5
x=-5 x=-1
(x+3)²=9
(x+3)²-9=0
x+3=3
x=3-3
x=0
x+3=-3
x=-3-3
x=-6
ответ:x=-6 x=-5 x=-1 x=0