Упростите выражений(абвг)

Решите задачу:

$\sqrt{\pi^2-8\pi+16} = \sqrt{(\pi-4)^2} =|\pi-4|=4-\pi \\\ \sqrt{(2- \sqrt{5})^2 } + \sqrt{(3- \sqrt{5})^2 } = \\\ =|2- \sqrt{5}|+|3- \sqrt{5}|= \sqrt{5}-2+3- \sqrt{5}=1$

$\sqrt{4\pi^2-28\pi+49} = \sqrt{(2\pi-7)^2} =|2\pi-7|=7-2\pi \\\ \sqrt{(2.7- \sqrt{7})^2 } + \sqrt{(2.6- \sqrt{7})^2 } = \\\ =|2.7- \sqrt{7}|+|2.6- \sqrt{7}|=2.7- \sqrt{7}+ \sqrt{7}-2.6=0.1$