Помогите, пожалуйста!

Решите задачу:

$\frac{2y}{u(u+2y)};\;\frac y{u(z-3u)};\;\frac{z+6y}{u(z-3u)+2y(z-3u)}\\\frac{2y}{u(u+2y)};\;\frac y{u(z-3u)};\;\frac{z+6y}{(u+2y)(z-3u)}\\\frac{2y(z-3u)}{u(u+2y)(z-3u)};\;\frac{y(u+2y)}{u(u+2y)(z-3u)};\;\frac{u(z+6y)}{u(u+2y)(z-3u)}\\\frac{2yz-6yu}{u(u+2y)(z-3u)};\;\frac{yu+2y^2}{u(u+2y)(z-3u)};\;\frac{uz+6yu}{u(u+2y)(z-3u)}\\\\OTBET\;\#4$