Решить систему уравнений

$\left \{ {{3log_2 x+4log_3 (y+1)=11} \atop {4log_2 x+log_3(y+1)=6}} \right.$
ОДЗ: x>0;y>-1
$\left \{ {{3log_2 x+4log_3 (y+1)=11} \atop {log_3(y+1)=6-4log_2 x}} \right.$
$\left \{ {{3log_2 x+4(6-4log_2 x)=11} \atop {log_3(y+1)=6-4log_2 x}} \right.$
$\left \{ {{3log_2 x+24-16log_2 x=11} \atop {log_3(y+1)=6-4log_2 x}} \right.$
$\left \{ {{-13log_2 x=-13} \atop {log_3(y+1)=6-4log_2 x}} \right.$
$\left \{ {{log_2 x=1} \atop {log_3(y+1)=6-4log_2 x}} \right.$
$\left \{ {{x=2} \atop {log_3(y+1)=6-4log_2 x}} \right.$
$\left \{ {{x=2} \atop {log_3(y+1)=6-4log_2 2}} \right.$
$\left \{ {{x=2} \atop {log_3(y+1)=2}} \right.$
$\left \{ {{x=2} \atop {log_3(y+1)=log_3 9}} \right.$
$\left \{ {{x=2} \atop {y+1=9}} \right.$
$\left \{ {{x=2} \atop {y=8}} \right.$