Log3 xy=2+log3 log3 x+y=2

Question

Log3 xy=2+log3 log3 x+y=2

Answer 1

Log4(x+y)=2*Log4(4)
Log4(x+y)=Log4(16)
x+y=16
Log3x+Log3y=2+Log37
Log3(xy)=Log3(9)+Log3(7)
Log3(xy)=Log3(63)
xy=63

x+y=16        x=16-y

xy=63    (16-y)y=63
-y²+16y-63=0
y²-16y+63=0
D<0⇒ решений нет</span>