8sinx+9sin^2 x+9cos^2 x=8

Question

8sinx+9sin^2 x+9cos^2 x=8

Answer 1

8sinx + 9(sin^2x + cos^2x) = 8 
8sinx + 9 = 8 
8sinx = - 1
sinx = - 1/8 
x = (-1)^(k+1) arcsin (1/8) + pik, k ∈Z

Comments

Спасибо братюнь! :)