Решите неравенство, пожалуйста)

Решите задачу:

$\left ( \frac{1}{5} \right )^{\frac{2x+1}{1-x}}\ \textgreater \ 125\\\\5^{-\frac{2x+1}{1-x}}\ \textgreater \ 5^3\\\\5^{\frac{2x+1}{x-1}}\ \textgreater \ 5^3\\\\ \frac{2x+1}{x-1}\ \textgreater \ 3\\\\ \frac{2x+1}{x-1}-3\ \textgreater \ 0\\\\ \frac{2x+1-3x+3}{x-1} \ \textgreater \ 0\\\\ \frac{-x+4}{x-1}\ \textgreater \ 0\\\\ \frac{x-4}{x-1} \ \textless \ 0\\\\+++(1)---(4)+++\\\\x\in (1,4)$