㏒₀,₃(3x-9)≤ ㏒₀,₃(4x-11)

$\log _{0.3}(3x-9) \leq \log _{0.3}(4x-11)$

ОДЗ:
$\left \{ {{3x-9\ \textgreater \ 0} \atop {4x-11\ \textgreater \ 0}} \right. \to \left \{ {{3x\ \textgreater \ 9} \atop {4x\ \textgreater \ 11}} \right. \to \left \{ {{x\ \textgreater \ 3} \atop {x\ \textgreater \ 2.75}} \right.$
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$x \in (3; +\infty )$

$3x-9 \geq 4x-11 \\ 3x-4x \geq -11+9 \\ -x \geq -2 \\ x \leq 2$

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C учетом ОДЗ неравенство не имеет решений.