(х-3)^2+(3-х)(х+3)=(х+2)^2-х^2

Question

(х-3)^2+(3-х)(х+3)=(х+2)^2-х^2

Answer 1

(х-3)^2+(3-х)(х+3)=(х+2)^2-х^2
x^2-6x+9+9-x^2=x^2+4x+4-x^2
-6x+18=4x+4
-10x= -14
x=1,4

Answer 2

Х² - 2×3×х + 3² + 9 - х²= х² + 2×2×х + 2² - х².
х² - 6х + 9+ 9 - х² - 4х - 4 + х² = 0.
х² - 10х + 14= 0.
Д= b² - 4ac=  (-10)² - 4×1×14= 100 - 56= 44.