Решите уравнение: (9х4)5 * (3х)3 ____________ = - 192 (27х5)4

$\frac{(9x^{4})^{5}\cdot(3x)^{3}}{(27x^{5})^{4}}=-192$

$\frac{(9)^{5}\cdot(x^{4})^{5}\cdot(3)^{3}\cdot(x)^{3}}{(27)^{4}\cdot(x^{5})^{4}}=-192$

$\frac{(3^{2})^{5}\cdot x^{(4\cdot5)}\cdot(3)^{3}\cdot x^{(1\cdot3)}}{(3^{3})^{4}\cdot x^{(5\cdot4)}}=-192$

$\frac{(3^{(2\cdot5)}\cdot x^{20}\cdot(3)^{3}\cdot x^{3}}{3^{(3\cdot4)}\cdot x^{20}}=-192$

$\frac{3^{10}\cdot x^{20}\cdot3^{3}\cdot x^{3}}{3^{12}\cdot x^{20}}=-192$

$\frac{(3^{10}\cdot3^{3})\cdot(x^{20}\cdot x^{3})}{3^{12}\cdot x^{20}}=-192$

$\frac{3^{(10+3)}\cdot x^{(20+3)}}{3^{12}\cdot x^{20}}=-192$

$\frac{3^{13}\cdot x^{(20+3)}}{3^{12}\cdot x^{20}}=-192$

$\frac{3^{(12+1)}\cdot x^{20}\cdot x^{3}}{3^{12}\cdot x^{20}}=-192$

$\frac{3^{12}\cdot3^{1}\cdot x^{20}\cdot x^{3}}{3^{12}\cdot x^{20}}=-192$

$\frac{3^{12}\cdot3\cdot x^{20}\cdot x^{3}}{3^{12}\cdot x^{20}}=-192$

$\frac{(3^{12}\cdot x^{20})\cdot (3\cdot x^{3})}{(3^{12}\cdot x^{20})}=-192$

сокращаем остаётся

$3x^{3}=-192$

$x^{3}=-192:3$

$x^{3}=-64$

$x=-4$