Выполнить действие с дробями 12,3/5-7,1/6+2,3/10=?

1 способ.
$\frac{12,3}{5}- \frac{7,1}{6}+ \frac{2,3}{10}=\frac{12,3*6}{30}- \frac{7,1*5}{30}+ \frac{2,3*3}{30}= \frac{73,8}{30}- \frac{35,5}{30}+ \frac{6,9}{30}=$
$\frac{73,8-35,5+6,9}{30} = \frac{45,2}{30}=\frac{452}{300}= \frac{113}{75}= 1\frac{38}{75}$
2 способ.
$\frac{12,3}{5}- \frac{7,1}{6}+ \frac{2,3}{10}=\frac{123}{50}- \frac{71}{60}+ \frac{23}{100}=\frac{123*6}{300}- \frac{71*5}{300}+ \frac{23*3}{300}=$
$\frac{738-355+69}{300} = \frac{452}{300}= \frac{113}{75}= 1\frac{38}{75}$