Дано
m((NH4)2SO4))=250 kg = 250000g
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n(NH3)-?
m(NH3)-?
V(NH3)-?
Xg 250000
2NH3+H2SO4-->(NH4)2SO4
2*17 132
M(NH3)=17 g/mol
M(NH4)2SO4 = 132 g/mol
X=34*250000/132=64394 g
n(NH3)=m/M=64394 /17=3788 mol
V(NH3)=n*Vm=3788*22.4=84851.2 л
ответ 64394 г, 3788 моль , 84851.2 л