Дано
m(BaSO4)=466 g
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n(BaO)-?
m(BaO)-?
n(H2SO4)-?
m(H2SO4)-?
X X1 466 g
H2SO4+BaO-->BaSO4+H2O
98 153 233
M(H2SO4)=98 g/mol
M(BaO)=153 g/mol
M(BaSO4)=233 g/mol
X(H2SO4)=98*466/233=196 g
n(H2SO4)=m/M=196/98 = 2 mol
X1(BaO)=153*466/233=306 g
n(BaO)=306/153 = 2 mol
ответ H2SO4 - 196 g , 2 mol; BaO - 306g, 2 mol