Помогите решить пример номер 638 (б)

Решите задачу:

$1)\;2\frac2{15}+2\frac7{10}=2\frac4{30}+2\frac{21}{30}=4\frac{25}{30}=4\frac56=\frac{29}6\\2)\;2\frac7{10}-2\frac2{15}=2\frac{21}{30}-2\frac4{30}=\frac{17}{30}\\3)\;\frac{29}6:1\frac2{27}=\frac{29}6:\frac{29}{27}=\frac{29}6\cdot\frac{27}{29}=\frac12\cdot\frac9{1}=\frac92=4\frac12\\4)\;\frac{17}{30}:2\frac37=\frac{17}{30}:\frac{17}7=\frac{17}{30}\cdot\frac7{17}=\frac7{30}\\5)\;4\frac12-\frac7{30}=4\frac{15}{30}-\frac7{30}=4\frac8{30}=4\frac4{15}$