1)
2HCOOH+Mg-->(HCOO)2Mg+H2
2CH3-CH2COOH+CaO-->(CH3CH2COO)2Ca+H2O
HCOOH+KOH-->HCOOK+H2O
2HCOOH+Na2CO3-->2HCOONa+H2O+CO2
CH3-CH2-COOH+HO-CH2-CH3-->CH3-CH2-COOCH2-CH3+H2O
HCOOH+Ag2O-->HO-COOH+2Ag
угольная к-та + серебро
2))
дано
m(CH3COOH)=120 g
m(практ CH3COOCL2)=170 g
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η-?
120g Xg
CH3COOH+CL2-->CH3COOCL+HCL
44 78.5
M(CH3COOH)=44 g/mol
M(CH3COOCL)=78.5g/mol
X=120*78.5/44
X=214.09 g - масса теоретическая
η=170/214.09*100%=79.4%
ответ 79.4%