Помогите ПЖ 300б даю Cos (Pi(4x-9))/4 =√2/2
Решение Cos (Pi(4x-9))/4 =√2/2 (Pi(4x-9))/4 = (+ -)arccos(√2/2) + 2πk, k ∈ Z πx - 9π/4 = (+ -)* (π/4) + 2πk, k ∈ Z πx = (+ -)* (π/4) + 9π/4 + 2πk, k ∈ Z x = (+ -)* (1/4) + 9/4 + 2k, k ∈ Z