Решите уравнение номер 2... только с проверкой плиз... я решила.. и ответ с учебником...

Решите задачу:

$\frac23(5t-2)-\frac34(3t+1)=3-\frac{2t+1}2\;\;\;\;\;\times12\\8(5t-2)-9(3t+1)=36-6(2t+1)\\40t-16-27t-9=36-12t-6\\40t-27t+12t=36-6+16+9\\25t=55\\t=\frac{55}{25}=\frac{11}5=2\frac15\\\\\Pi POBEPKA:\\\frac23(5\cdot\frac{11}5-2)-\frac34(3\cdot\frac{11}5+1)=\frac23(11-2)-\frac34(\frac{33}5+1)=\\=\frac23\cdot9-\frac34\cdot\frac{38}5=6-\frac{57}{10}=6-5\frac7{10}=\frac3{10}\\3-\frac{2\cdot\frac{11}5+1}2=3-\frac{\frac{22}5+1}2=3-\frac{\frac{27}5}2=3-\frac{27}{10}=3-2\frac7{10}=\frac3{10}\\\frac3{10}=\frac3{10}$