(x^2-3)(x+2)+(x^2+3)(x-2)=4 (x^2-1)(x-4)+(x^2+1)(x+4)=6

Question

(x^2-3)(x+2)+(x^2+3)(x-2)=4
(x^2-1)(x-4)+(x^2+1)(x+4)=6

Answer 1

(x^2-3)(x+2)+(x^2+3)(x-2)=4
x^3+2x^2-3x-6+x^3-2x^2+3x-6=4
2x^3-12=4
2x^3=4+12
2x^3=16
x^3=8
x^3=2^3
x=2