(2х^2-5х-7)(х-1)=0 Х^2-9х=0

Question

(2х^2-5х-7)(х-1)=0
Х^2-9х=0

Answer 1

(2х^2-5х-7)=0 или
(х-1)=0, тогда X1=(5+(25+56)^(1/2))/4=(5+9)/4=3.5 x2=(5-(25+56)^(1/2))/4=(5-9)/4=-1 x3=1

Х^2-9х=0
X*(x-9)=0
X=0 или х=9