Номер 597 по математике 1) (2/7 + 3 целых 1/2 ) × 4 целых 2/ 32) (4 целых 1/5-2 целых...

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$1.\;\left(\frac27+3\frac12\right)\cdot4\frac23=\left(\frac27+\frac72\right)\cdot\frac{14}3=\left(\frac4{14}+\frac{49}{14}\right)\cdot\frac{14}3=\frac{53}{14}\cdot\frac{14}3=\frac{53}3=17\frac23\\\\2.\;\left(4\frac15-2\frac34\right)\cdot2\frac2{17}=\left(\frac{21}5-\frac{11}4\right)\cdot\frac{36}{17}=\left(\frac{84}{20}-\frac{55}{20}\right)\cdot\frac{36}{17}=\frac{29}{20}\cdot\frac{36}{17}=3\frac6{85}$

$3.\;\left(5\frac67+3\frac5{21}\right)\cdot2\frac1{10}=\left(\frac{41}7+\frac{68}{21}\right)\cdot\frac{21}{10}=\frac{123+68}{21}\cdot\frac{21}{10}=\frac{191}{21}\cdot\frac{21}{10}=19\frac1{10}\\\\4.\;\left(7\frac5{12}-3\frac16\right)\cdot2\frac2{17}=\left(\frac{89}{12}-\frac{19}6\right)\cdot\frac{36}{17}=\frac{89-38}{12}\cdot\frac{36}{17}=\frac{51}{12}\cdot\frac{36}{17}=3\cdot3=9$